If it's not what You are looking for type in the equation solver your own equation and let us solve it.
12t^2+16t-60=0
a = 12; b = 16; c = -60;
Δ = b2-4ac
Δ = 162-4·12·(-60)
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3136}=56$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-56}{2*12}=\frac{-72}{24} =-3 $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+56}{2*12}=\frac{40}{24} =1+2/3 $
| 3x+4=72x−1 | | 12t^2+16t-60t=0 | | 2x+9=3(15-x) | | 8=5+y/7.68 | | 5x-4+3x+8=8 | | 4x2-24x+7=3 | | 6x/2=18 | | 12x^2=-8 | | 2(4x+5)=7x+8 | | -2(x-1)=5-2x | | 5-5(2x-2)=-25 | | 5(2x+7)-9x=36 | | -9^2-6z+15=0 | | -9n+11=-8n-3 | | 6x-6+9x=-6+5x+10 | | (x+7)(4x+3)=-21 | | 8(s+7)=100-35 | | 4^(x+2)=16C | | 3x-1+2/7(7x-2)=-11/7 | | x/4=1/16 | | n+28=9 | | d=9/2 | | 25/30=5/j | | 5(v-1)=9v+7 | | -11x-2=24 | | -6u+24=9(u-9) | | 8(y+4)=3y+27 | | -9u+29=-7(u-3) | | 6(u+1)=2u-18 | | 6u-32=-2(u+4) | | 16=4(v-4)-8v | | -2y+9=8y+21 |